the value of 'a' for which the polynomial 4x^4-2x^3-3x^2-ax-28 has -2 as it's zero
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Answered by
6
Answer:
the answer will be
4(-2)*4-2(-2)³-3(-2)²-a(-2)-28
64+16-12+2a-28
64+4+2a-28
68+2a-28=0
2a+40=0
a=-20
Answered by
2
Answer:
Step-by-step explanation:
Hey!!!!!
We have
=> 2x⁴ - ax³ + 4x² + 2x + 1 = p(x)
Thus for the divisiblity of 1 - 2x
=> 1 - 2x = 0
=> x = 1/2
Thus P(1/2) = 0
=> 2(1/2)⁴ - a(1/2)³ + 4(1/2)² + 2(1/2) + 1 = 0
=> 2(1/16) - a(1/8) + 4(1/4) + 1 + 1 = 0
=> 1/8 - a/8 + 1 + 1 + 1 = 0
=> 1/8 - a/8 + 3 = 0
=> a/8 = 25/8
=> a = 25
Hope this helps ✌️
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