The value of "a" for which the polynomial 4x⁴+2x³-3x²-ax-28 has -2 as its zero is
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a = -4
Solution :
• Note : The possible values of the variable (here x) for which the polynomial becomes zero are called its zeros .
ie ; If x = a is a zero of the polynomial p(x) , then p(a) = 0 .
Here ,
The given polynomial is ;
4x⁴ + 2x³ - 3x² - ax - 28 .
Let the given polynomial be p(x) .
Thus ,
p(x) = 4x⁴ + 2x³ - 3x² - ax - 28
Also ,
It is given that , x = -2 is a zero of the given polynomial p(x) .
Thus ,
=> p(-2) = 0
=> 4•(-2)⁴ + 2•(-2)³ - 3•(-2)² - a•(-2) - 28 = 0
=> 64 - 16 - 12 + 2a - 28 = 0
=> 2a + 8 = 0
=> 2a = -8
=> a = -8/2
=> a = -4
Hence , a = -4 .
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