Question

the value of a for which (x+a) is a factor of x^3 + ax^2 - 3x + 16 + a is​

Answer 1

Answer:

a=4

Step-by-step explanation:

by factor theorem if u out in equation 2 value of x= -a than result be zero

so,

after putting value of x equal to a

(-a)³+(-a)(-a)²-3(-a)+16+a= 0

=⟩. -2a³+4a+16=0

=⟩ 2a³= 4a+16

=⟩. 2a(a-2)= 16

=⟩. a(a-2) = 8

so a = 4

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