Question

the value of a if the division of ax³+9x²+4x-10 by x+3 leaves a remainder 5...........but the answer is (x-3)²(x-1)plzs​

Answer 1

Hi,friend!!✌

I loved your question...

Answer:-

Answer:-k=2

Here is your answer.

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If , p(x)= kx³+9x²+4x-10

Then, p(-3) = 5 [ By the remainder theorem x-(-3)]

So, k(-3)³+9(-3)²+4(-3)-10 = 5

=> -27k + 81 - 12 -10 = 5

=> -27k + 81 = 5 + 10 + 12

=> -27k= 27-81

=> k = -54\-27

=> k = 2

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Hope it helps you......

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