The value of a in ax^3+2x^2-x+3a-7 when the factor is x+1
Answers
Answered by
0
If the factor is x+1 then it will satisfy ax^3+2x^2-x+3a-7=0
substitute x= -1 in given equation and solve to get value of a
a(-1)^3+2(-1)^2-(-1)+3a-7=0\
-a+ 2 + 1 + 3a -7=2a-4=0
a=2
Please mark as brainliest if you think the answer helped
Answered by
0
Step-by-step explanation:
BY EVALUATION :-
ax3+2x2−x+3a−7
Evaluate for x=1
a(13)+2(12)−1+3a−7
=4a−6
BY SIMPLIFYING:-
Let's simplify step-by-step.
ax3+2x2−x+3a−7
=ax3+2x2+−x+3a+−7
Answer:
=ax3+2x2+3a−x−7
Similar questions