the value of a land is increased by 20% it is now 18000 what was the price of the land before increse in price?????
answer is 15000 now plz.... answer with full solution and correctly plz... reply fast
Answers
Answered by
34
Let the price of the land before increase be x.
x + 20% of x = 18000
x + 20x/100 = 18000
x + x/5 = 18000
6x/5 = 18000
6x = 90000
x = 15000.
Therefore the price of the land before the increase was 15000.
Hope this helps!
x + 20% of x = 18000
x + 20x/100 = 18000
x + x/5 = 18000
6x/5 = 18000
6x = 90000
x = 15000.
Therefore the price of the land before the increase was 15000.
Hope this helps!
Answered by
30
☆Hey Mate!!!☆
Let the original value be x
If we increase 20%, then = x + 20x/100
And increased value is also 18000
So, x + 20x/100 = 18000
( 100x + 20x ) / 100 = 18000
120x/100 = 18000
x = 18000 × 100/120
= 15,000
Yet any confusion! leave a comment or inbox.
☺☺☺!
Let the original value be x
If we increase 20%, then = x + 20x/100
And increased value is also 18000
So, x + 20x/100 = 18000
( 100x + 20x ) / 100 = 18000
120x/100 = 18000
x = 18000 × 100/120
= 15,000
Yet any confusion! leave a comment or inbox.
☺☺☺!
ShuchiRecites:
thanks for brainliest
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