Question

The value of a land is increased by 30%. It is now ₹13000. What was the price before increase in price

Answer 1

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$\sf{\underline{\boxed{\large{\blue{\mathsf{Solution}}}}}}$

$\sf{\bold{\green{\underline{\underline{Given}}}}}$

• value increased by = 30%
• Current price = Rs. 13000

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$\sf{\bold{\green{\underline{\underline{To\:Find}}}}}$

• Old value / price = ???

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$\sf{\bold{\green{\underline{\underline{Solution}}}}}$

• let the old price be x

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$\sf{\bold{ old\:price \:+ increment \:= \: new\:price}}$

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$\sf{\bold{ x + \dfrac{30 x} { 100 } = 13000}}$

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$\sf{\bold{ x + \dfrac{3 x} { 10} = 13000}}$

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$\sf{\bold{ \dfrac{10x + 3 x} { 10 } = 13000}}$

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$\sf{\bold{ \dfrac{13 x} { 10 } = 13000}}$

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$\sf{\bold{ x = \dfrac{ 13000 \times 10}{13}}}$

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$\sf{\bold{ x = 1000 \times 10 }}$

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$\sf{\bold{ x = Rs. 10000 }}$

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$\sf{\bold{\green{\underline{\underline{Answer}}}}}$

• Old price before increment was Rs. 10000

Answer 2

Answer:

»Question :-

• The value of a land is increased by 30%. It is now ₹13000. What was the price before increase in price

»Answer:-

$\sf{ \bold{ \green{solution {}{} }{} }{} }{}$

• Value increased = 30%

• Current prize = 13000

$\sf{ \bold{ \orange{to \: find \: out}{} }{} }{}$

Old Value /old price = ___?

$\sf{ \bold{ \blue{detailed \: answer}{} }{} }{}$

Let the old prize be = x

$\bold{ \pink{old \: price +increment =new \: prize}{}{}}$

$\sf{ \purple{x + \frac{30x}{100 } = 13000rs }{} }{}$

>> x+3x/10 = ₹13000

10x+3x/10 = 13000

13x/10 = 13000

x = 13000*10/13

• x = 1000*10
• x = 10000

$\sf{ \bold{ \red{old \: price \: = \: 10000}{} }{} }{}$

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