Question

the value of a^logax

Answer 1

Answer: A) x

Step-by-step explanation:

Let

a^logaX = P.

Taking log with base a both sides

loga(a^logaX) = logaP

logaX * logaa = logaP.

logaX = logaP

So, X = P

a^logaX = X

Answer 2

Answer:

$a^{log_{a}x } = x$

Step-by-step explanation:

Let,

$a^{log_{a}x }$= M

Taking log with base a in both sides we can get,

$log_{a}^{a}$  .  $log_{a}^{x}$ = $log_{a}^{M}$

As $log_{a}^{a} = 1$,

$log_{a}^{x} =log_{a}^{M}$

∴$x=M$

Hence it can be concluded that, $a^{log_{a}x } = x$

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