Math, asked by vikasgugnani230, 19 days ago

the value of a machine depreciates 5% every year if the present value of the machine is 24000 what will be its value after 2 year

Answers

Answered by Ishitjain30
2

Answer:

21660

Step-by-step explanation:

initial value=24000

5% of decrease in first year=24000-24000x5/100=22800

Then,5% decrease in second year= 22800-22800x5/100=21660

Answered by shrihankp
0

Answer:

 21,660

Step-by-step explanation:

Present value  x =  24000

Annual Depreciation rate  {r}_{d} =  5\%

Time period  n =  2

Value after two years

=  x\left(1-\dfrac{{r}_{d}}{100}\right)^n

=  24000\left(1-\dfrac{5}{100}\right)^2

=  24000\left(1-\dfrac{1}{20}\right)^2

=  24000\left(\dfrac{19}{20}\right)^2

=  24000\left(\dfrac{361}{400}\right)

=  21660

Hence, the value of the machine after two years will be  21,660

Similar questions