Question

the value of a machine depreciates at rate of 10% per annum it was purchased 3 years ago if its present value is rupees 291600 for how much was purchase​

Answer 1

Answer:

Let the principal be ₹x

amount =8,748

time =3 years.

Amount = p(1-r/100)power n ( when rate is d-

epreacting)

A/q

8748 = x(1-10/100)power 3

==> 8748=x ×9/10×9/10×9/10

==>8748= x × 729/1000

==>8748×1000= x × 729

==>8748000/728 =x

==>12000=x

hence x = 12000

so , the machine was purchased in ₹ 12000

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