Physics, asked by kurmila1235, 7 months ago

the value of a machine depreciates at the rate of 12% p.a. if its present value is 7000 rupees .what will be its value after 2 years.​

Answers

Answered by sarojkumaraditri
1

Answer:

We know that

Final price = initial price(1+

100

rate

)

time

Here the final price = Rs. 8784, time =3 yrs, rate =−10%p.a.

The rate is negative since the price is depriciating.

Let the initial price = Rs. x.

∴x×(1−

100

10

)

3

=8748

⇒x×

10

9

×

10

9

×

10

9

=8748

⇒x=8748×

9

10

×

9

10

×

9

10

= Rs. 12000

So, the price of the machine 3 years back = Rs. 12000.

Ans- Option C.

Answered by abhi178
4

Given info : the value of a machine depreciates at the rate of 12 % p.a. the present value of its price is 7000 Rs.

To find : the value of after 2 years is ...

solution : the value of the machine depreciates at the rate of 12 per annum.

after n years, the value of the machine will be, A = A₀(1 - r/100)ⁿ

here initial value of the machine = A₀ = 7000 Rs

the rate of depreciation = r = 12 % per annum

time = n = 2 years

⇒ A = 7000(1 - 12/100)² = 7000 × 23/25 × 23/25 = 5924.8 Rs.

therefore the value of the machine after 2 years is 5924.8 Rs.

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