Question

the value of a machine depreciates at the rate of 20% every year. it was purchased 3 years ago. if its present value is Rs.9000, what was it purchase price?​

Answer 1

Answer:

Let the purchase price = ₹ x

a/q

$x \times (1 - \frac{20}{100} ) {}^{3} = 9000 \\ x \times \frac{4}{5} \times \frac{4}{5} \times \frac{4}{5} = 9000 \\ x = \frac{9000 \times 5 \times 5 \times 5}{4 \times 4 \times 4} = 17578.125 \\ ans.$