the value of a machine depreciates every year by 10% if its present value is 80000,what will be the population value after 2 years
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value of machine after 1 year = 10% of 80000
= 10/100×80000= 8000
= 80000-8000= 72000
Cost after 2 year = 10% of 72000
= 10/100×72000= 7200
72000-7200 = 64800
cost after 2 year= 64800
= 10/100×80000= 8000
= 80000-8000= 72000
Cost after 2 year = 10% of 72000
= 10/100×72000= 7200
72000-7200 = 64800
cost after 2 year= 64800
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