The value of a machine depreciates every year by 20%. If the present value of the machine be 160000 rs, what was its value last year?
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The formula of depreciation is
P(1-R/100)^n=A
Here,
P = Principal [We have to calculate]
R = 20% [Rate]
A= 160000 [Amount]
n = 1 [Time in Years]
P(1-20/100)¹ = 160000
=>P×4/5 = 160000
=>P = 200000 Rs.
The value of that machine last year is 200000Rs.
Hope it helps
P(1-R/100)^n=A
Here,
P = Principal [We have to calculate]
R = 20% [Rate]
A= 160000 [Amount]
n = 1 [Time in Years]
P(1-20/100)¹ = 160000
=>P×4/5 = 160000
=>P = 200000 Rs.
The value of that machine last year is 200000Rs.
Hope it helps
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