the value of a machine depreciates every year by 20 percent. if the present value of the machine be rupees 160000,what was it's value of last year?
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Answered by
246
Hey!
Let the value be 100x last year.
Value is depreciated 20% that means
= 100x-100x*20/100 = 80x.
This year's price= 80x
Also this year's price=160000.
So 80x= 160000.
x= 160000/80. = 2000.
100x= 2000*100.
= 200000Rs.
Last year the machine's value was 200000Rs.
Hope it helps.
Let the value be 100x last year.
Value is depreciated 20% that means
= 100x-100x*20/100 = 80x.
This year's price= 80x
Also this year's price=160000.
So 80x= 160000.
x= 160000/80. = 2000.
100x= 2000*100.
= 200000Rs.
Last year the machine's value was 200000Rs.
Hope it helps.
from where 80 is come
100x - 20% of 100 as the depreciation is 20%.
Answered by
148
hope it help you...............
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not profit and loss
i know but we can solve it by this formula. it is also correct
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welcome. this formula is from compound interest
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