Math, asked by ayush736, 1 year ago

the value of a machine depreciates every year by 20 percent. if the present value of the machine be rupees 160000,what was it's value of last year?

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Answers

Answered by kushanaanandp4ac8a

246

Hey!

Let the value be 100x last year.
Value is depreciated 20% that means
= 100x-100x*20/100 = 80x.
This year's price= 80x
Also this year's price=160000.

So 80x= 160000.
x= 160000/80. = 2000.
100x= 2000*100.
= 200000Rs.
Last year the machine's value was 200000Rs.

Hope it helps.

ayush736: from where 80 is come

kushanaanandp4ac8a: 100x - 20% of 100 as the depreciation is 20%.

Answered by anni5580

148

hope it help you...............

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ayush736: not profit and loss

anni5580: i know but we can solve it by this formula. it is also correct

ayush736: ok

ayush736: thank

anni5580: welcome. this formula is from compound interest

ayush736: happy I mark you in brainlist

anni5580: thanks

ayush736: sorry you are right I am confused

ayush736: can you follow me

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