Question

The value of a machine depreciates from Rs 32,768 to Rs 21,952 in three years. What is the rate % of depreciation?​

Answer 1

Answer:

12.5%

Explanation:

A=P(1-R/100)^n

Principal = 32768

Amount = 21952

Timeb= 3 years

21952=32768(1-R/100)^3

21952/32768=(1-R/100)^3

7/8 = 1-R/100

1/8 = R/100

R = 100/8 = 12.5 %