Question

the value of a machine reduces by 20% every year.if the present value is 15000Rs.what will its value be 2 years late?

Answer 1

Price of Machine at present = Rs. 15000
Reducement every year = 20%
Price of machine after a year
= 15000-15000×20%
= 15000-3000
= Rs. 12000

Here, New price = Rs. 12000
Again, Reducement = 20%
therefore, new price of machine
= 12000-12000×20%
= 12000-2400
= Rs. 9600
so, Price of machine after two years
= Rs. 9600

Answer 2

$a = p {(1 + \frac{r}{100}) }^{t} \\ a = 15000 {(1 + \frac{20}{100} )}^{2} \\ a = 15000 \times( { \frac{120}{100} )}^{2} \\ a = 15000 \times \frac{120 \times 120}{100 \times 100} \\ a = 150 \times 144 \\ a = 21600$
2 YEARS LATER BUS VALUE WILL BECOME 21600.

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