-) The value of a machine worth 5,00,000 depreciates at the rate of 10% every
year. In how many years will its value be * 3,64,500?
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Answer:
Present value = 500000
Reduced value = 364500
Rate of depreciation = 10% p.a.
Consider n years as the period
We know that
A/P = (1−r/100)n
Substituting the values
364500/500000=(1−10/100)n
By further calculation
(9/10)n=729/1000=(9/10)3
So we get
n=3
Therefore, the period in which its value be reduced to 364500 is 3 years.
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