Question

the value of a machine worth rupees 500000 is depreciating at the rate of 10% every year. in how many years will its value be reduced to rupees 364500?

Answer 1

amount=Rs.364500

principal= Rs.500000

rate of decreasement=10%

now,

        A=P(1-R/100)^n

        364500                 =500000(1-10/100)^n

        364500/500000  =(10-1/10)n

        729/1000                =(9/10)^n

       ( 9/10)^3                      =(9/10)^n

n=> 3 year Ans!