Question

The value of a motoe cycle depreciates at the rste of 15% per year, what will be the valur of the motor cycle 3 year hence, which is now purchased for
₹45,000

Answer 1

Answer:

$required \: value = 45000 \times (1 - \frac{15}{100} ) {}^{3} \\ = 45000 \times \frac{85}{100} \times \frac{85}{100} \times \frac{85}{100} = \\ \frac{45 \times 85 \times 85 \times 85}{1000} = \\ 27635.625 \: \: ans.$

Answer 2

Given :

• Value of motor = ₹45,000
• Rate of depreciation = 15%
• Time = 3years

To Find :

• The value of the motor cycle at the 3rd year

Solution :

a = ₹45,000

Depreciation = 15% for ₹45,000

= 45000 × 15/100

= 450 × 15

= 6750

d = ₹6750

since it is depreciation,

d = -6750

★ At the end of 1st year :

= ₹45000 - ₹6750

= ₹38250

Again depreciation = 38250 × 15/100

= 3825 × 15/10

= 57375 / 10

= 5737.50

★ At the end of 2nd year :

= At the end of 1st year - Depreciation of the First year

= ₹38250 - ₹5737.50

= 32512.50

Again depreciation = 32512.50 × 15/100

= 487687.5 / 100

= 4876.87

★ At the end of 3rd year :

= At the end of 2nd year - Depreciation of the 2nd year

= 32512.50 - 4876.87

= 27635.63

•°• The value of motor cycle at the the 3rd year = ₹27636