Question

.The value of a property decreases every year al the rate of 5%. If its value at the end of 3 years is 14,11,540, what was the original value at the beginning of these three years ?









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Answer 1

Answer:

A] present value = Rs 411540

rate of depreciation = 5% p.a

t = 3 years

value 3 yrs ago=p(1−

100

R

)

n

⇒411540=p(1−

100

5

)

3

⇒411540=p(

100

95

)

3

⇒411540=p(

20

19

)

3

⇒411540=p(

8000

6859

)

3

⇒

6859

411540×80000

=Rs480000

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Answer 2

Step-by-step explanation:

A] present value =Rs 411540

rate of depreciation = 5% p.a

t = 3 years

value 3 yrs ago=p(1

100

R

)

n

→ 411540=p(1

100

5

3

F

411540=p(

100

95

)

3

→ 411540=p(

20

19

)

3

→

411540=p(8000 6859)

3

6859

411540x80000=Rs480000

hope it helps you.. k