Question

The value of a property decreases every year at the rate of 5%. If its present value is 411540, what was its value three years ago?




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Answer 1

Answer:

480000

Step-by-step explanation:

A=P(1-r/100)n

411540=P(1-(5/100))^3

411540=P(95/100)^3

411540=P(19/20)^3

411540=P(6859/8000)

P=411540÷(6859/8000)

P=411540×(8000/6859)

P=480000

Answer 2

Answer:

Heya ✋

Let see your answer !!!!

Given that

Present value of property = ₹4,11,540

Rate of depreciation = 5 % p.a.

Time = 3 years

Solution

Value of property 3 years ago = P(1 - R/100)^n

=> 4,11,540 = P(1 - 5/100)^3

=> 4,11,540 = P(100 - 5/100)^3

=> 4,11,540 = P(95/100)^3

=> 4,11,540 = P(19/20)^3

=> 4,11,540 = P × 6,859/8,000

=> P = 4,11,540 × 8,000/6,859

=> P = ₹4,80,000

Thanks :))))

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Step-by-step explanation: