the value of a property decreases every year at the rate of 5%. If its present value is Rs 411540, what was it's value 3years ago.
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Answered by
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Heya ✋
Let see your answer !!!!
Given that
Present value of property = ₹4,11,540
Rate of depreciation = 5 % p.a.
Time = 3 years
Solution
Value of property 3 years ago = P(1 - R/100)^n
=> 4,11,540 = P(1 - 5/100)^3
=> 4,11,540 = P(100 - 5/100)^3
=> 4,11,540 = P(95/100)^3
=> 4,11,540 = P(19/20)^3
=> 4,11,540 = P × 6,859/8,000
=> P = 4,11,540 × 8,000/6,859
=> P = ₹4,80,000
Thanks :))))
Let see your answer !!!!
Given that
Present value of property = ₹4,11,540
Rate of depreciation = 5 % p.a.
Time = 3 years
Solution
Value of property 3 years ago = P(1 - R/100)^n
=> 4,11,540 = P(1 - 5/100)^3
=> 4,11,540 = P(100 - 5/100)^3
=> 4,11,540 = P(95/100)^3
=> 4,11,540 = P(19/20)^3
=> 4,11,540 = P × 6,859/8,000
=> P = 4,11,540 × 8,000/6,859
=> P = ₹4,80,000
Thanks :))))
XtraordinaryABHI:
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355503.7253
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