Math, asked by XtraordinaryABHI, 1 year ago

the value of a property decreases every year at the rate of 5%. If its present value is Rs 411540, what was it's value 3years ago.

Answers

Answered by Anonymous
54
Heya ✋

Let see your answer !!!!

Given that

Present value of property = ₹4,11,540

Rate of depreciation = 5 % p.a.

Time = 3 years

Solution

Value of property 3 years ago = P(1 - R/100)^n

=> 4,11,540 = P(1 - 5/100)^3

=> 4,11,540 = P(100 - 5/100)^3

=> 4,11,540 = P(95/100)^3

=> 4,11,540 = P(19/20)^3

=> 4,11,540 = P × 6,859/8,000

=> P = 4,11,540 × 8,000/6,859

=> P = ₹4,80,000









Thanks :))))

XtraordinaryABHI: Thanks
Answered by shreya3363
12

Answer:

355503.7253

look at the pic

Attachments:
Similar questions