the value of a scooter depreciates by 10% every year if the present value is 20000 rupees what was its value 2 years ago
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Step-by-step explanation:
p= 20000
r= 10%
t=2
price is decreasing so,
A= p(1-r/100)ⁿ
= 20000(1-10/100)²
= 20000(1-1/10)²
=20000(9/10)²
= 20000×81/100
= 200×81
= 16200
hence price of scooter after 2 year is 16200
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