Question

the value of a ^ x^=​

Answer 1

Answer:

Option (4) x = 0.

Step-by-step explanation:

a^x = a ^-x^2 + 1 / a ^ -x^2 + 1

a^x = a^ -x^2 + 1 -( -x^2 +1)

a^x = a^ -x^2 +1 + x^2 - 1

a^x = a^ 0

Or

x = 0

Hence

Option (4) x = 0 is the answer.

Now,

To find a^x^2 :

a^x^2 = a^0^2

= a^0 (since 0^2 = 0)

= 1.

Note :

▶Identity used :

a^x/ a^y = a^x -y

a^x = a^y

then x = y.