The value of a' x al will be:
![{a}^{9} \times {a}^{7} {a}^{9} \times {a}^{7}](https://tex.z-dn.net/?f=+%7Ba%7D%5E%7B9%7D++%5Ctimes++%7Ba%7D%5E%7B7%7D+)
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Answer:
a⁹*a⁷
(m^n*m^o=m^n+o)
a⁹+⁷
a¹⁶
hope it helps
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