the value of a²+b²+2ab+2bc+2ca when a+b=10 and c=5 is
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( a+b+c)² =a² +b²+c² +2ab+2bc +2ca
= (10+5)² = a²+b²+(5)²+2ab +2bc+2ca
= (15)²-(5)²= a²+b²++2ab+2bc+2ca
so a²+b²+2ab+2bc+2ca = 225 -25 = 200
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