Question

The value of
(a²-b²)³+(b²-c²)³+(c²-a²)³
(a - b)³+(b-c)³+(c-a)³
is​

Answer 1

a−c)[(a−b)2+(b−c)2−(a−b)(b−c)]+(c−a)3

=(a−c)[(a−b)2+(b−c)2−(a−b)(b−c)]−(a−c)3

=(a−c)[(a−b)2+(b−c)2−(a−b)(b−c)−(a−c)2]

=(a−c)[(a2+b2−2ab)+(b2+c2−2bc)−(ab−ac−b2+bc)−(a2+c2−2ac)]

=(a−c)[a2+b2−2ab+b2+c2−2bc−ab+ac+b2−bc−a2−c2+2ac]

=(a−c)[3b2−3ab−3bc+3ac]

=3(a−c)[b(b−a)−c(b−a)]

=3(a−c)(b−c)(b−a)

=3(a−b)(b−c)(c−a)

Answer 2

Answer:

3(a-b)(b-c)(c-a)

Step-by-step explanation:

i hope your doubt is clear