Question

The value of a³+3a²b+3ab²+b³ ,at a=(-2) and b=(3)​

Answer 1

Answer:

1

Step-by-step explanation:

a^3+3a^2b+3ab^2+b^3

if u look carefully this is a identity

(a+b)^3 = a^3 + 3ab(a+b) + b^3

and this identity is further opened

= a^3 + 3a^2b+ 3ab^2 + b^3

so now by putting in the values of 'a' as -2 and

'b' as 3

it will be

(-2+3)^3

=(1)^3

=1

so ur answer is 1