Question

The value of acceleration and friction force in the given diagram is ???

Ms = 0.4 MK = 0.3 12

F = 500 N

1) 4 m/s2 upward, 120 N (2) 4 m/s2 downward, 120 N (3) 5 m/s2 upward, 36 N (4) 5 m/s2 upward, 120 N ind lan 2​

Answer 1

As the lift is moving at a uniform speed, acceleration a=0

R=mg=70×10⇒700N

Reading on the weighing scale 

        =700/g=700/10=70kg