Physics, asked by omswaroop1986, 10 months ago

the value of accleration due to gravity on the surface of earth is x .at attitude of h from the surface of the earth ,its value is y . if r is the radius of earth ,then the values of h is...

Answers

Answered by aadarshjha
1

Explanation:

at the surface of the earth,

x=GM/r^2---(1)

at the height h,

y=GM/(r+h)^2----(2)

dividing 1 by 2 we get

x/y =(r+h)^2/r^2

xr^2/y=(r+h)^2

r+h=✓(x/y) r

h=✓x/y r-r

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