Question

The value of AGⓇ for the phosphorylation
of glucose in glycolysis is 13.8 kJ/mol.
Find the value of K at 298 K.​

Answer 1

I think this helps you

ΔG0=−RTlnK

13.8×mol103J=−(molK)8.314(J)(298)(K)lnKc

lnKc=−8.314×29813.8×103

Kc=10−5.57=10−6+0.43

Kc=10−6×100.43=2.69×10−6