Question

The value of AG for the phosphorylation
of glucose in glycolysis is 13.8 kJ/mol
Find the value of K at 298 K.​

Answer 1

Answer:

ΔG

0

=−RTlnK

13.8×

mol

10

3

J

=−

(molK)

8.314(J)

(298)(K)lnK

c

lnK

c

=−

8.314×298

13.8×10

3

K

c

=10

−5.57

=10

−6+0.43

K

c

=10

−6

×10

0.43

=2.69×10

−6