Question

The value of AGº for the phosphorylation of glucose in glycolysis is 13.8 kJ/mol. Find the value
of K, at 298 K.
​

Answer 1

Answer:

Explanation:

ANSWER

ΔG  

0

=−RTlnK

13.8×  

mol

10  

3

J

​  

=−  

(molK)

8.314(J)

​  

(298)(K)lnK  

c

​  

 

lnK  

c

​  

=−  

8.314×298

13.8×10  

3

 

​  

 

K  

c

​  

=10  

−5.57

=10  

−6+0.43

 

K  

c

​  

=10  

−6

×10  

0.43

=2.69×10  

−6