The value of alpha for which the shortest distance between the lines y z
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Consider first equation of the line z-0 y-0 Comparing with x- X1 y-Yi b1 z-z1 we get C1 %3D = X1 = 0, y1 = 0, z1 = 0, az = 2, b1 = 3, c = 1 Consider second equation of the line x-2 y-1 z+2 2 -5 y-1 z-(-2) %3D Comparing with x-X2 - y-V2 -2-Z2 b2 C2 az - X2 = 2, y2 = 1, Z2 = -2, az = 3, b2 = - 5, c2 = 2 Using shortest distance formula, |X2 - X1 Y2 Vi 22-21 b1 C1 b2 az C2 (b,c2 -b2c) + (c,az - ajc2)? + (a,b2 -azbı)?
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