Question

THE VALUE OF AN EQUIPMENT FROM ₹6000 DEPRECATES TO ₹5415 IN 2 YEARS, FIND THE RATE OF DEPRECIATION?


please see photo too and answer ASAP

Answer 1

Answer:

........ FOLLOW ME FOR GETTING ANSWER ❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️

Answer 2

Solution :

Given,

Value after 2 years (R) = Rs. 5415

Duration (D) = 2 years

Note: i = rate of depreciation

We know that,

$\implies$ $\huge{\boxed{\sf{R = S (1 - i)^{D}}}}$

By substituting the values,

$\implies$ $\sf{5415 = 6000(1 - i) ^{2}}$

$\implies$ $\sf{ \frac{5415}{6000} = (1 - i) ^{2}}$

$\implies$ $\sf{0.9025 = {(1 - i)}^{2}}$

Now:

$\implies$ $\sf{ \sqrt{(0.9025)} = 1 - i}$

$\implies$ $\sf{0.95 = 1 - i}$

So:

$\implies$ $\sf{i = 1 - 0.95}$

$\implies$ $\sf{i = 0.05}$

$\implies$ $\sf{i = 5\%}$

Therefore,

The rate of depreciation is 5%.

_________________

Answered by: Niki Swar, Goa❤️