the value of ax^2+bx+c at x= -b/a
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Hi usaid is the question correct please check and tell
marzukamustaque:
from iit math Ahh??
no
Ok bye
what means at x
it is in the question
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Answer: step-by-step explanation
=ax^2+bx+c. x=-b/a
=a(-b/a)^2+b(-b/a)+c
=a×b^2/a^2 +b×-b/a+c (a divided by a^2 which is denominator of b^2 & b multiplied by -b)
=b^2/a -b^2/a +c (+ signed b^2/a canceled by - signed b^2/a)
=c is the answer
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