Math, asked by dipankar836, 6 months ago

the value of ax²+bx+c at x = - b/a is​

Answers

Answered by urmiladangi887
1

Answer:

ax²+bx+c

Step-by-step explanation:

x= -b/a

a(-b/a)² +b(-b/a) +c

a× b²/a² -b²/a +c

b²/a -b²/a +c

c

Answered by brokendreams
0

Step-by-step explanation:

Given : A quadratic equation ax^{2} +bx+c.

To find : The value of equation at  x=\frac{-b}{a}.

  • Calculating value of equation at x=\frac{-b}{a}.

We have,

⇒  ax^{2} +bx+c=0.

and we have to find the value of equation at x=\frac{-b}{a}.

substituting \frac{-b}{a} in place of x,

⇒  a*(\frac{-b}{a})^{2} +b(\frac{-b}{a})+c

⇒  a*\frac{b^{2} }{a^{2} } -\frac{b^{2} }{a}+c

⇒  \frac{b^{2} }{a}-\frac{b^{2} }{a}+c

⇒  c

Hence, the value of equation at  x=\frac{-b}{a} is c .

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