Math, asked by ashutoshdadhich633, 1 month ago

the value of 'b' is option a 3 option b 5 option c 7 option d 11

Answers

Answered by ansulsharma
0

Correct option is

Correct option isA

Correct option isA−2

Correct option isA−2A(3,1)B(5,P)C(7,−5)

Correct option isA−2A(3,1)B(5,P)C(7,−5)If points A(x

Correct option isA−2A(3,1)B(5,P)C(7,−5)If points A(x 1

Correct option isA−2A(3,1)B(5,P)C(7,−5)If points A(x 1

Correct option isA−2A(3,1)B(5,P)C(7,−5)If points A(x 1 ,y

Correct option isA−2A(3,1)B(5,P)C(7,−5)If points A(x 1 ,y 1

Correct option isA−2A(3,1)B(5,P)C(7,−5)If points A(x 1 ,y 1

Correct option isA−2A(3,1)B(5,P)C(7,−5)If points A(x 1 ,y 1 ),B(x

Correct option isA−2A(3,1)B(5,P)C(7,−5)If points A(x 1 ,y 1 ),B(x 2

Correct option isA−2A(3,1)B(5,P)C(7,−5)If points A(x 1 ,y 1 ),B(x 2

Correct option isA−2A(3,1)B(5,P)C(7,−5)If points A(x 1 ,y 1 ),B(x 2 ,y

Correct option isA−2A(3,1)B(5,P)C(7,−5)If points A(x 1 ,y 1 ),B(x 2 ,y 2

),C(x

),C(x 3

),C(x 3

),C(x 3 ,y

),C(x 3 ,y 3

),C(x 3 ,y 3

),C(x 3 ,y 3 ) are collinear then

),C(x 3 ,y 3 ) are collinear thenar(△ABC)=

),C(x 3 ,y 3 ) are collinear thenar(△ABC)= 2

),C(x 3 ,y 3 ) are collinear thenar(△ABC)= 21

),C(x 3 ,y 3 ) are collinear thenar(△ABC)= 21

),C(x 3 ,y 3 ) are collinear thenar(△ABC)= 21 [x

),C(x 3 ,y 3 ) are collinear thenar(△ABC)= 21 [x 1

),C(x 3 ,y 3 ) are collinear thenar(△ABC)= 21 [x 1

),C(x 3 ,y 3 ) are collinear thenar(△ABC)= 21 [x 1 (y

),C(x 3 ,y 3 ) are collinear thenar(△ABC)= 21 [x 1 (y 2

y

y 3

y 3

y 3 )+x

y 3 )+x 2

y 3 )+x 2

y 3 )+x 2 (y

y 3 )+x 2 (y 3

−y

−y 1

−y 1

−y 1 )+x

−y 1 )+x 3

−y 1 )+x 3

−y 1 )+x 3 (y

−y 1 )+x 3 (y 1

−y 1 )+x 3 (y 1

−y 1 )+x 3 (y 1 −y

−y 1 )+x 3 (y 1 −y 2

−y 1 )+x 3 (y 1 −y 2

−y 1 )+x 3 (y 1 −y 2 )]=0

−y 1 )+x 3 (y 1 −y 2 )]=02

−y 1 )+x 3 (y 1 −y 2 )]=021

−y 1 )+x 3 (y 1 −y 2 )]=021

−y 1 )+x 3 (y 1 −y 2 )]=021 [3[5+p)+5(−5−1)+7(1−p)]=0

(−5−1)+7(1−p)]=015+3p−30+7−7p=0

(−5−1)+7(1−p)]=015+3p−30+7−7p=04p=−15+7

(−5−1)+7(1−p)]=015+3p−30+7−7p=04p=−15+74p=−8

(−5−1)+7(1−p)]=015+3p−30+7−7p=04p=−15+74p=−8p=−2

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