Question

The value of charge varies as q=2t-6t*2+10t*3 what is the time after which the current will be at its maximum value

Answer 1

Answer:

The final temperature if 50 g of water at 0oc is added to 250 g of water at 90oc.

It is the maximum temperature it can reach.

Answer 2

Answer:

1/5s

Explanation:

(i) q=2t−6t2+10t3

Current ,I=dqdt=2−12t+30t2

(ii) I=2−12t+30t2….(i)

I will be maximum or minimum when

dI/dt=0−12+60t or t=12/60=1/5s