Math, asked by bindulucky8, 4 months ago

The value of cos^2 63º - sin^2 27°​

Answers

Answered by pjsidharth2004
2

Answer:

sin²27° = sin²(90-63°)

= cos²63°

so, cos²63°- sin²27°= cos²63°-cos²63°=0

hope this helps...

Answered by DibyenduChakraborty
1

cos^2 63º - sin^2 27°

= cos² 63° - sin² 27°

= cos² (90° - 27°) - sin² 27°

[as, (90° - 27°) = 63°]

= sin² 27° - sin²27°

[as, son ∅ = cos (90° - ∅)]

= 0.

please mark me brainlist

Similar questions