The value of cos 2a/(1 - sin 2a) is
0
1
tan a
tan(45° + a)
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Answered by
3
Answer:
Cot( A - B)
= ( CotA cotB+1)/(cotB-cotA)
Now,
LHS = cot( 45 - A) =
= ( CotAcot45° + 1)/( cotA - cot45)
= ( CotA +1)/( cotA - 1)
= ( CosA/sinA +1)/( cosA/sinA - 1)
= (CosA+sinA)?/(cosA+sinA)(COSA-sinA)
= (cos?A+sin A+2sinAcosA)/(cos A-sin? A)
= (1 + 2sinAcosA) / cos2A
= (1 + sin2A ) /cos2A
I hope this helps you:)
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Answered by
1
Q) The value of cos 2a/(1 - sin 2a) is
0
1
tan a
tan(45° + a)
ANSWER:-
refer this atterment
hope it is help you
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