The value of cos (3π/2)^c is
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Answer:
Correct option is
A
2
π
We have, cos
−1
(cos
2
3π
)
=cos
−1
cos(2π
2
π
) [∵cos(2π−
2
π
)]=cos
2
π
=cos
−1
cos(
2
π
)=
2
π
{∵cos
−1
(cosx)=x,x∈[0,π]}
Note remember that, cos
−1
(cos
2
3π
)
=
2
3π
∵
2
3π
∈(0,π)
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