Math, asked by heresomeone13, 9 months ago

The value of cos (3π/2)^c is​

Answers

Answered by navdeepbawa9
0

Answer:

Correct option is

A

2

π

We have, cos

−1

(cos

2

)

=cos

−1

cos(2π

2

π

) [∵cos(2π−

2

π

)]=cos

2

π

=cos

−1

cos(

2

π

)=

2

π

{∵cos

−1

(cosx)=x,x∈[0,π]}

Note remember that, cos

−1

(cos

2

)

=

2

2

∈(0,π)

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