Question

the value of cos(60+2A)÷cos 2A-√3 sin 2A

Answer 1

cos(60° + 2A) / (cos2A - √3 sin2A) = 1/2

Step-by-step explanation:

∴ cos(60° + 2A) / (cos2A - √3 sin2A)

= cos(60° + 2A) / {2 * (1/2 cos2A - √3/2 sin2A)}

= cos(60° + 2A) / {2 * (cos60° cos2A - sin60° sin2A)}

= cos(60° + 2A) / {2 * cos(60° + 2A)}

= 1/2

Trigonometry:

Trigonometry is the study of relations between angles and their ratios with various properties to find sine, cosine, tan, cosec, sec and cot ratios. Some properties can deduce angles in their general value apart from known definite ones. Now let us know some identities-

1. sin²θ + cos²θ = 1

2. sec²θ - tan²θ = 1

3. cosec²θ - cot²θ = 1

4. cos(A + B) = cosA cosB - sinA sinB

5. cos(A - B) = cosA cosB + sinA sinB

6. sin(A + B) = sinA cosB + cosA sinB

7. sin(A - B) = sinA cosB - cosA sinB

8. sin60° = √3 / 2

9. cos60° = 1/2

Answer 2

Answer:

Heya!!

Step-by-step explanation:

Refer to the attachment!!