Question

The value of cos 62° cos 17°+ sin 62° sin 17°is​

Answer 1

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Answer 2

cos 62° cos 17°+ sin 62° sin 17° = 1/√2

Given :

cos 62° cos 17°+ sin 62° sin 17°

To find :

The value of the expression

Formula :

cos A cos B + sin A sin B = cos ( A - B )

Solution :

Step 1 of 2 :

Write down the given expression

The given expression is

cos 62° cos 17°+ sin 62° sin 17°

Step 2 of 2 :

Find the value of the expression

We are aware of the formula on Trigonometry that

cos A cos B + sin A sin B = cos ( A - B )

We take A = 62° & B = 17°

Thus we get

cos 62° cos 17°+ sin 62° sin 17°

= cos ( 62° - 17° )

= cos 45°

= 1/√2

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