Question

the value of cos square 60 degree + sin square 30 degree + 2sec square 45 degree + cot 45 degree is

Answer 1

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Answer 2

$\cos^2 60^\circ +\sin^2 30\circ+2\sec^2 45^\circ+\cot 45^\circ=\frac{11}{2}$

Step-by-step explanation:

Given : Expression $\cos^260^\circ +\sin^2 30\circ+2\sec^2 456\circ+\cot 45^\circ$

To find : The value of the expression ?

Solution :

$\cos^2 60^\circ +\sin^2 30\circ+2\sec^2 45^\circ+\cot 45^\circ$

Using trigonometric values,

$\cos 60^\circ=\frac{1}{2}$

$\sin 30^\circ=\frac{1}{2}$

$\sec 45^\circ=\sqrt2$

$\cot 45^\circ=1$

Substitute the values,

$=(\frac{1}{2})^2+(\frac{1}{2})^2+2(\sqrt2)^2+1$

$=\frac{1}{4}+\frac{1}{4}+2(2)+1$

$=\frac{1}{2}+5$

$=\frac{1+10}{2}$

$=\frac{11}{2}$

Therefore, $\cos^2 60^\circ +\sin^2 30\circ+2\sec^2 45^\circ+\cot 45^\circ=\frac{11}{2}$

#Learn more

Evaluate the following sin 30 degrees + tan 45 degrees minus cos tan 60 degrees by cos 45 degrees + Cos 60 degrees minus secant 30 degrees​

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