Question

The value of cos48°+sin42° is

Answer 1

Answer:

Hi Mate Here Is Your Answer

Step-by-step explanation:

Consider cos48

0

which can be rewritten as follows:

cos48

0

=cos(90

0

−42

0

)=sin42

0

(∵cos(90

0

−x)=sinx)

Therefore, cos48

0

−sin42

0

can be evaluated as shown below:

cos48

0

−sin42

0

=sin42

0

−sin42

0

=0

Hence, cos48

0

−sin42

0

=0.

Hope It Helps

Answer 2

Answer:

The value of cos48°+sin42° is zero

Step-by-step explanation:

cos480=cos(900−420)=sin420

(∵cos(900−x)=sinx)

Therefore, cos480−sin420can be evaluated as shown below:

cos480−sin420=sin420−sin420

                         =0

Hence, cos480−sin420

=0.

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