Question

the value of cos54°/ tan36°+tan20°/cot70° is​

Answer 1

/* There is mistake in the question , it should be like this */

$The\:value \: of \: \frac{cot 54}{tan 36 } + \frac{tan 20}{cot 70 }$

$= \frac{cot (90-36)}{tan 36 } + \frac{tan (90-20)}{cot 70 }$

$=\frac{tan 36}{tan 36 } + \frac{cot 70}{cot 70 }$

$= 1 + 1$

$= 2$

Therefore.,

$\red{The\:value \: of \: \frac{cot 54}{tan 36 } + \frac{tan 20}{cot 70 }}\green { = 2}$

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Answer 2

Answer:

2

Step-by-step explanation:

=> cot54°/tan36° + tan20°/cot70°

=> cot(90-36)/tan36 + tan(90-20)/cot70

=> tan36/tan36 + cot70/cot70

=> 1+1

=> 2

hence the value is "2 "

hope it helps ! ♥️