the value of cosA if secA - tanA = m + 1/m.
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Answer:
m
2
−1
=
(secA+tanA)
2
+1
(secA+tanA)
2
−1
=
sec
2
A+tan
2
A+2secAtanA+1
sec
2
A+tan
2
A+2secAtanA−1
=
sec
2
A+(tan
2
A+1)+2secAtanA
(sec
2
A−1)+tan
2
A+2secAtanA
=
2sec
2
A+2secAtanA
2tan
2
A+2secAtanA
=
2secA
2tanA
=
cosA
sinA
×cosA=sinA
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