Question

the value of
cosA /tan A+secA - cosA /tanA−sec A is
a) 2 b) -2 c) 0 d) 1

Answer 1

Step-by-step explanation:

=(cosAtanA-cosAsecA) - (cosAtanA+cosAsecA)/(tan^2 A - sec^2 A)

=((sinA/cos^2 A)-1) -((sinA/cos^2 A)+1)/1

=(sinA-cos^2 A/ cos^2 A) - (sinA+cos^2 A/ cos^2 A)

=-2cos^2 A/cos^2 A

=-2